Buffalo Rumblings
Atlanta Falcons running back Bijan Robinson has been named the NFC Offensive Player of the Week for his performance against the Buffalo Bills in Week 6. Robinson totaled 238 yards of offense and one touchdown on 25 touches.
The Bills were completely over-matched in trying to contain Robinson, who broke off an 81-yard touchdown run in the second quarter to put the Falcons ahead for good. In the first half alone, Robinson had 12 carries for 138 yards and that touchdown. In all, Robinson carried 19 times for 170 yards, adding six receptions (8 targets) for 68 more yards. Robinson was a major factor in the passing game during the second half, with one of his receptions netting a huge conversion as Atlanta was trying to use clock late in the fourth quarter.
By the time Buffalo had figured out a plan to slow down Robinson, the damage was done and it was too late to mount a comeback. Atlanta won 24-14, improving to 3-2, while the Bills dropped their second game in a row to fall to 4-2. Leading up to the Monday Night Football game, many had a feeling that Robinson would light up the box score as a true dual-threat player, and did he ever.
The running back Renaissance continues in 2025, and Robinson is off to a hot start with just under 500 yards rushing to go along with 338 yards receiving. to date he has just three total touchdowns, but Robinson’s explosiveness makes him a threat to go the distance any time he touches the football. Even when teams try to take him out of the game plan, Robinson has the elusiveness to make defenders miss and drive defensive coordinators crazy.
Usually when it comes to the offensive player of the week awards we here at Buffalo Rumblings are writing about a Bills player winning something after a game. Whether it be quarterback Josh Allen or running back James Cook, opposing teams are usually on the receiving end of these awards. This time however, the shoe is on the other foot as Buffalo’s defense allowed Bijan Robinson to run wild in one half of football.
